2(4+4b+b)-2b=16

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Solution for 2(4+4b+b)-2b=16 equation:



2(4+4b+b)-2b=16
We move all terms to the left:
2(4+4b+b)-2b-(16)=0
We add all the numbers together, and all the variables
2(5b+4)-2b-16=0
We add all the numbers together, and all the variables
-2b+2(5b+4)-16=0
We multiply parentheses
-2b+10b+8-16=0
We add all the numbers together, and all the variables
8b-8=0
We move all terms containing b to the left, all other terms to the right
8b=8
b=8/8
b=1

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