2(4+4x)=7(x-1)

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Solution for 2(4+4x)=7(x-1) equation:



2(4+4x)=7(x-1)
We move all terms to the left:
2(4+4x)-(7(x-1))=0
We add all the numbers together, and all the variables
2(4x+4)-(7(x-1))=0
We multiply parentheses
8x-(7(x-1))+8=0
We calculate terms in parentheses: -(7(x-1)), so:
7(x-1)
We multiply parentheses
7x-7
Back to the equation:
-(7x-7)
We get rid of parentheses
8x-7x+7+8=0
We add all the numbers together, and all the variables
x+15=0
We move all terms containing x to the left, all other terms to the right
x=-15

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