2(4+6c)=56

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Solution for 2(4+6c)=56 equation: 



2(4+6c)=56

We move all terms to the left:

2(4+6c)-(56)=0

We add all the numbers together, and all the variables

2(6c+4)-56=0

We multiply parentheses

12c+8-56=0

We add all the numbers together, and all the variables

12c-48=0

We move all terms containing c to the left, all other terms to the right

12c=48

c=48/12

c=4

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