2(4+h)=6(2h-1)

Solution for 2(4+h)=6(2h-1) equation:

2(4+h)=6(2h-1)

We move all terms to the left:

2(4+h)-(6(2h-1))=0

We add all the numbers together, and all the variables

2(h+4)-(6(2h-1))=0

We multiply parentheses

2h-(6(2h-1))+8=0


We calculate terms in parentheses: -(6(2h-1)), so:

6(2h-1)

We multiply parentheses

12h-6

Back to the equation:

-(12h-6)


We get rid of parentheses

2h-12h+6+8=0

We add all the numbers together, and all the variables

-10h+14=0

We move all terms containing h to the left, all other terms to the right

-10h=-14

h=-14/-10

h=1+2/5