2(4+k)=3(k-6)

Solution for 2(4+k)=3(k-6) equation:

2(4+k)=3(k-6)

We move all terms to the left:

2(4+k)-(3(k-6))=0

We add all the numbers together, and all the variables

2(k+4)-(3(k-6))=0

We multiply parentheses

2k-(3(k-6))+8=0


We calculate terms in parentheses: -(3(k-6)), so:

3(k-6)

We multiply parentheses

3k-18

Back to the equation:

-(3k-18)


We get rid of parentheses

2k-3k+18+8=0

We add all the numbers together, and all the variables

-1k+26=0

We move all terms containing k to the left, all other terms to the right

-k=-26

k=-26/-1

k=+26