2(4+x)-(3x-4)=8-2(x-2)+x

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Solution for 2(4+x)-(3x-4)=8-2(x-2)+x equation: 



2(4+x)-(3x-4)=8-2(x-2)+x

We move all terms to the left:

2(4+x)-(3x-4)-(8-2(x-2)+x)=0

We add all the numbers together, and all the variables

2(x+4)-(3x-4)-(8-2(x-2)+x)=0

We multiply parentheses

2x-(3x-4)-(8-2(x-2)+x)+8=0

We get rid of parentheses

2x-3x-(8-2(x-2)+x)+4+8=0



We calculate terms in parentheses: -(8-2(x-2)+x), so:

8-2(x-2)+x

determiningTheFunctionDomain
-2(x-2)+x+8

We add all the numbers together, and all the variables

x-2(x-2)+8

We multiply parentheses

x-2x+4+8

We add all the numbers together, and all the variables

-1x+12

Back to the equation:

-(-1x+12)



We add all the numbers together, and all the variables

-1x-(-1x+12)+12=0

We get rid of parentheses

-1x+1x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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