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2(4+x)=9-3(x+1)
We move all terms to the left:
2(4+x)-(9-3(x+1))=0
We add all the numbers together, and all the variables
2(x+4)-(9-3(x+1))=0
We multiply parentheses
2x-(9-3(x+1))+8=0
We calculate terms in parentheses: -(9-3(x+1)), so:We get rid of parentheses
9-3(x+1)
determiningTheFunctionDomain -3(x+1)+9
We multiply parentheses
-3x-3+9
We add all the numbers together, and all the variables
-3x+6
Back to the equation:
-(-3x+6)
2x+3x-6+8=0
We add all the numbers together, and all the variables
5x+2=0
We move all terms containing x to the left, all other terms to the right
5x=-2
x=-2/5
x=-2/5
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