2(4-2r)=-2(r+5)+8r

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Solution for 2(4-2r)=-2(r+5)+8r equation: 



2(4-2r)=-2(r+5)+8r

We move all terms to the left:

2(4-2r)-(-2(r+5)+8r)=0

We add all the numbers together, and all the variables

2(-2r+4)-(-2(r+5)+8r)=0

We multiply parentheses

-4r-(-2(r+5)+8r)+8=0



We calculate terms in parentheses: -(-2(r+5)+8r), so:

-2(r+5)+8r

We add all the numbers together, and all the variables

8r-2(r+5)

We multiply parentheses

8r-2r-10

We add all the numbers together, and all the variables

6r-10

Back to the equation:

-(6r-10)



We get rid of parentheses

-4r-6r+10+8=0

We add all the numbers together, and all the variables

-10r+18=0

We move all terms containing r to the left, all other terms to the right

-10r=-18

r=-18/-10

r=1+4/5

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