2(4-2r)=-4r(r+2)

Solution for 2(4-2r)=-4r(r+2) equation:

2(4-2r)=-4r(r+2)

We move all terms to the left:

2(4-2r)-(-4r(r+2))=0

We add all the numbers together, and all the variables

2(-2r+4)-(-4r(r+2))=0

We multiply parentheses

-4r-(-4r(r+2))+8=0


We calculate terms in parentheses: -(-4r(r+2)), so:

-4r(r+2)

We multiply parentheses

-4r^2-8r

Back to the equation:

-(-4r^2-8r)


We get rid of parentheses

4r^2+8r-4r+8=0

We add all the numbers together, and all the variables

4r^2+4r+8=0

a = 4; b = 4; c = +8;
Δ = b2-4ac
Δ = 42-4·4·8
Δ = -112
Delta is less than zero, so there is no solution for the equation