2(4-3)=9u+1-2(-4u-1)

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Solution for 2(4-3)=9u+1-2(-4u-1) equation:



2(4-3)=9u+1-2(-4u-1)
We move all terms to the left:
2(4-3)-(9u+1-2(-4u-1))=0
We add all the numbers together, and all the variables
-(9u+1-2(-4u-1))+21=0
We calculate terms in parentheses: -(9u+1-2(-4u-1)), so:
9u+1-2(-4u-1)
determiningTheFunctionDomain 9u-2(-4u-1)+1
We multiply parentheses
9u+8u+2+1
We add all the numbers together, and all the variables
17u+3
Back to the equation:
-(17u+3)
We get rid of parentheses
-17u-3+21=0
We add all the numbers together, and all the variables
-17u+18=0
We move all terms containing u to the left, all other terms to the right
-17u=-18
u=-18/-17
u=1+1/17

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