2(4-3)=9u+1-2(-4u-1)

Solution for 2(4-3)=9u+1-2(-4u-1) equation:

2(4-3)=9u+1-2(-4u-1)

We move all terms to the left:

2(4-3)-(9u+1-2(-4u-1))=0

We add all the numbers together, and all the variables

-(9u+1-2(-4u-1))+21=0


We calculate terms in parentheses: -(9u+1-2(-4u-1)), so:

9u+1-2(-4u-1)

determiningTheFunctionDomain
9u-2(-4u-1)+1

We multiply parentheses

9u+8u+2+1

We add all the numbers together, and all the variables

17u+3

Back to the equation:

-(17u+3)


We get rid of parentheses

-17u-3+21=0

We add all the numbers together, and all the variables

-17u+18=0

We move all terms containing u to the left, all other terms to the right

-17u=-18

u=-18/-17

u=1+1/17