2(4-4)=-3(y+2)+8

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Solution for 2(4-4)=-3(y+2)+8 equation:


Simplifying
2(4 + -4) = -3(y + 2) + 8

Combine like terms: 4 + -4 = 0
2(0) = -3(y + 2) + 8

Multiply 2 * 0
0 = -3(y + 2) + 8

Anything times zero is zero.
0 = -3(y + 2) + 8

Reorder the terms:
0 = -3(2 + y) + 8
0 = (2 * -3 + y * -3) + 8
0 = (-6 + -3y) + 8

Reorder the terms:
0 = -6 + 8 + -3y

Combine like terms: -6 + 8 = 2
0 = 2 + -3y

Solving
0 = 2 + -3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '3y' to each side of the equation.
0 + 3y = 2 + -3y + 3y
Remove the zero:
3y = 2 + -3y + 3y

Combine like terms: -3y + 3y = 0
3y = 2 + 0
3y = 2

Divide each side by '3'.
y = 0.6666666667

Simplifying
y = 0.6666666667

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