2(4-5h)=3h2

Solution for 2(4-5h)=3h2 equation:

2(4-5h)=3h^2

We move all terms to the left:

2(4-5h)-(3h^2)=0

determiningTheFunctionDomain
-3h^2+2(4-5h)=0

We add all the numbers together, and all the variables

-3h^2+2(-5h+4)=0

We multiply parentheses

-3h^2-10h+8=0

a = -3; b = -10; c = +8;
Δ = b2-4ac
Δ = -102-4·(-3)·8
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-14}{2*-3}=\frac{-4}{-6}
=2/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+14}{2*-3}=\frac{24}{-6}
=-4
$