2(4-a+8a)=12+2(a+6a-2)

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Solution for 2(4-a+8a)=12+2(a+6a-2) equation: 


Simplifying
2(4 + -1a + 8a) = 12 + 2(a + 6a + -2)

Combine like terms: -1a + 8a = 7a
2(4 + 7a) = 12 + 2(a + 6a + -2)
(4 * 2 + 7a * 2) = 12 + 2(a + 6a + -2)
(8 + 14a) = 12 + 2(a + 6a + -2)

Reorder the terms:
8 + 14a = 12 + 2(-2 + a + 6a)

Combine like terms: a + 6a = 7a
8 + 14a = 12 + 2(-2 + 7a)
8 + 14a = 12 + (-2 * 2 + 7a * 2)
8 + 14a = 12 + (-4 + 14a)

Combine like terms: 12 + -4 = 8
8 + 14a = 8 + 14a

Add '-8' to each side of the equation.
8 + -8 + 14a = 8 + -8 + 14a

Combine like terms: 8 + -8 = 0
0 + 14a = 8 + -8 + 14a
14a = 8 + -8 + 14a

Combine like terms: 8 + -8 = 0
14a = 0 + 14a
14a = 14a

Add '-14a' to each side of the equation.
14a + -14a = 14a + -14a

Combine like terms: 14a + -14a = 0
0 = 14a + -14a

Combine like terms: 14a + -14a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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