2(4-c)=-4(5-3c)

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Solution for 2(4-c)=-4(5-3c) equation: 



2(4-c)=-4(5-3c)

We move all terms to the left:

2(4-c)-(-4(5-3c))=0

We add all the numbers together, and all the variables

2(-1c+4)-(-4(-3c+5))=0

We multiply parentheses

-2c-(-4(-3c+5))+8=0



We calculate terms in parentheses: -(-4(-3c+5)), so:

-4(-3c+5)

We multiply parentheses

12c-20

Back to the equation:

-(12c-20)



We get rid of parentheses

-2c-12c+20+8=0

We add all the numbers together, and all the variables

-14c+28=0

We move all terms containing c to the left, all other terms to the right

-14c=-28

c=-28/-14

c=+2

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