2(4-m)+4m=-(2+3m)=

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Solution for 2(4-m)+4m=-(2+3m)= equation: 



2(4-m)+4m=-(2+3m)=

We move all terms to the left:

2(4-m)+4m-(-(2+3m))=0

We add all the numbers together, and all the variables

2(-1m+4)+4m-(-(3m+2))=0

We add all the numbers together, and all the variables

4m+2(-1m+4)-(-(3m+2))=0

We multiply parentheses

4m-2m-(-(3m+2))+8=0



We calculate terms in parentheses: -(-(3m+2)), so:

-(3m+2)

We get rid of parentheses

-3m-2

Back to the equation:

-(-3m-2)



We add all the numbers together, and all the variables

2m-(-3m-2)+8=0

We get rid of parentheses

2m+3m+2+8=0

We add all the numbers together, and all the variables

5m+10=0

We move all terms containing m to the left, all other terms to the right

5m=-10

m=-10/5

m=-2

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