2(4-x)=x+3(x-2)

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Solution for 2(4-x)=x+3(x-2) equation: 



2(4-x)=x+3(x-2)

We move all terms to the left:

2(4-x)-(x+3(x-2))=0

We add all the numbers together, and all the variables

2(-1x+4)-(x+3(x-2))=0

We multiply parentheses

-2x-(x+3(x-2))+8=0



We calculate terms in parentheses: -(x+3(x-2)), so:

x+3(x-2)

We multiply parentheses

x+3x-6

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We get rid of parentheses

-2x-4x+6+8=0

We add all the numbers together, and all the variables

-6x+14=0

We move all terms containing x to the left, all other terms to the right

-6x=-14

x=-14/-6

x=2+1/3

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