2(4/5+5a/3)=-17/5+28a/3

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Solution for 2(4/5+5a/3)=-17/5+28a/3 equation:


a in (-oo:+oo)

2*((5*a)/3+4/5) = (28*a)/3-17/5 // - (28*a)/3-17/5

2*((5*a)/3+4/5)-((28*a)/3)-(-17/5) = 0

2*((5*a)/3+4/5)+(-28/3)*a+17/5 = 0

2*(5/3*a+4/5)+(-28*a)/3+17/5 = 0

(2*3*5*(5/3*a+4/5))/(3*5)+(-28*5*a)/(3*5)+(3*17)/(3*5) = 0

2*3*5*(5/3*a+4/5)-28*5*a+3*17 = 0

24-90*a+51 = 0

75-90*a = 0

(75-90*a)/(3*5) = 0

(75-90*a)/(3*5) = 0 // * 3*5

75-90*a = 0

75-90*a = 0 // - 75

-90*a = -75 // : -90

a = -75/(-90)

a = 5/6

a = 5/6

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