2(4/7x+4)=104/7

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Solution for 2(4/7x+4)=104/7 equation:



2(4/7x+4)=104/7
We move all terms to the left:
2(4/7x+4)-(104/7)=0
Domain of the equation: 7x+4)!=0
x∈R
We add all the numbers together, and all the variables
2(4/7x+4)-(+104/7)=0
We multiply parentheses
8x+8-(+104/7)=0
We get rid of parentheses
8x+8-104/7=0
We multiply all the terms by the denominator
8x*7-104+8*7=0
We add all the numbers together, and all the variables
8x*7-48=0
Wy multiply elements
56x-48=0
We move all terms containing x to the left, all other terms to the right
56x=48
x=48/56
x=6/7

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