2(41/2+m)+3=4(m-3)+51/2

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Solution for 2(41/2+m)+3=4(m-3)+51/2 equation: 



2(41/2+m)+3=4(m-3)+51/2

We move all terms to the left:

2(41/2+m)+3-(4(m-3)+51/2)=0



Domain of the equation: 2+m)!=0

We move all terms containing m to the left, all other terms to the right

m)!=-2

m!=-2/1

m!=-2

m∈R



We add all the numbers together, and all the variables

2(+m+41/2)-(4(m-3)+51/2)+3=0

We multiply parentheses

2m-(4(m-3)+51/2)+3+41/2*2=0

We calculate fractions


2m+(-(4(m-3)+51*2*2)/()+()/()+3=0

We can not solve this equation

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