2(45)=(3x+11)+(10x-12)

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Solution for 2(45)=(3x+11)+(10x-12) equation: 



2(45)=(3x+11)+(10x-12)

We move all terms to the left:

2(45)-((3x+11)+(10x-12))=0



We calculate terms in parentheses: -((3x+11)+(10x-12)), so:

(3x+11)+(10x-12)

We get rid of parentheses

3x+10x+11-12

We add all the numbers together, and all the variables

13x-1

Back to the equation:

-(13x-1)



We get rid of parentheses

-13x+1+245=0

We add all the numbers together, and all the variables

-13x+246=0

We move all terms containing x to the left, all other terms to the right

-13x=-246

x=-246/-13

x=18+12/13

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