2(47-1)=3(z+2)

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Solution for 2(47-1)=3(z+2) equation: 



2(47-1)=3(z+2)

We move all terms to the left:

2(47-1)-(3(z+2))=0

We add all the numbers together, and all the variables

-(3(z+2))+246=0



We calculate terms in parentheses: -(3(z+2)), so:

3(z+2)

We multiply parentheses

3z+6

Back to the equation:

-(3z+6)



We get rid of parentheses

-3z-6+246=0

We add all the numbers together, and all the variables

-3z+240=0

We move all terms containing z to the left, all other terms to the right

-3z=-240

z=-240/-3

z=+80

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