2(48-y)+4y=134

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Solution for 2(48-y)+4y=134 equation: 



2(48-y)+4y=134

We move all terms to the left:

2(48-y)+4y-(134)=0

We add all the numbers together, and all the variables

2(-1y+48)+4y-134=0

We add all the numbers together, and all the variables

4y+2(-1y+48)-134=0

We multiply parentheses

4y-2y+96-134=0

We add all the numbers together, and all the variables

2y-38=0

We move all terms containing y to the left, all other terms to the right

2y=38

y=38/2

y=19

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