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2(4X-10)=3(X+20)
We move all terms to the left:
2(4X-10)-(3(X+20))=0
We multiply parentheses
8X-(3(X+20))-20=0
We calculate terms in parentheses: -(3(X+20)), so:We get rid of parentheses
3(X+20)
We multiply parentheses
3X+60
Back to the equation:
-(3X+60)
8X-3X-60-20=0
We add all the numbers together, and all the variables
5X-80=0
We move all terms containing X to the left, all other terms to the right
5X=80
X=80/5
X=16
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