2(4a+2)=32+6a

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Solution for 2(4a+2)=32+6a equation: 



2(4a+2)=32+6a

We move all terms to the left:

2(4a+2)-(32+6a)=0

We add all the numbers together, and all the variables

2(4a+2)-(6a+32)=0

We multiply parentheses

8a-(6a+32)+4=0

We get rid of parentheses

8a-6a-32+4=0

We add all the numbers together, and all the variables

2a-28=0

We move all terms containing a to the left, all other terms to the right

2a=28

a=28/2

a=14

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