2(4a+8)=3(8a/3-10)

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Solution for 2(4a+8)=3(8a/3-10) equation: 


a in (-oo:+oo)

2*(4*a+8) = 3*((8*a)/3-10) // - 3*((8*a)/3-10)

2*(4*a+8)-(3*((8*a)/3-10)) = 0

2*(4*a+8)-3*((8*a)/3-10) = 0

2*(4*a+8)-3*(8/3*a-10) = 0

2*(4*a+8)-3*(8/3*a-10) = 0

46 = 0

46 = 0

a belongs to the empty set

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