2(4b+1)-4(b-3)=4(b+4)-2

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Solution for 2(4b+1)-4(b-3)=4(b+4)-2 equation:


Simplifying
2(4b + 1) + -4(b + -3) = 4(b + 4) + -2

Reorder the terms:
2(1 + 4b) + -4(b + -3) = 4(b + 4) + -2
(1 * 2 + 4b * 2) + -4(b + -3) = 4(b + 4) + -2
(2 + 8b) + -4(b + -3) = 4(b + 4) + -2

Reorder the terms:
2 + 8b + -4(-3 + b) = 4(b + 4) + -2
2 + 8b + (-3 * -4 + b * -4) = 4(b + 4) + -2
2 + 8b + (12 + -4b) = 4(b + 4) + -2

Reorder the terms:
2 + 12 + 8b + -4b = 4(b + 4) + -2

Combine like terms: 2 + 12 = 14
14 + 8b + -4b = 4(b + 4) + -2

Combine like terms: 8b + -4b = 4b
14 + 4b = 4(b + 4) + -2

Reorder the terms:
14 + 4b = 4(4 + b) + -2
14 + 4b = (4 * 4 + b * 4) + -2
14 + 4b = (16 + 4b) + -2

Reorder the terms:
14 + 4b = 16 + -2 + 4b

Combine like terms: 16 + -2 = 14
14 + 4b = 14 + 4b

Add '-14' to each side of the equation.
14 + -14 + 4b = 14 + -14 + 4b

Combine like terms: 14 + -14 = 0
0 + 4b = 14 + -14 + 4b
4b = 14 + -14 + 4b

Combine like terms: 14 + -14 = 0
4b = 0 + 4b
4b = 4b

Add '-4b' to each side of the equation.
4b + -4b = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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