2(4b+2)=4(3b+1)

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Solution for 2(4b+2)=4(3b+1) equation: 



2(4b+2)=4(3b+1)

We move all terms to the left:

2(4b+2)-(4(3b+1))=0

We multiply parentheses

8b-(4(3b+1))+4=0



We calculate terms in parentheses: -(4(3b+1)), so:

4(3b+1)

We multiply parentheses

12b+4

Back to the equation:

-(12b+4)



We get rid of parentheses

8b-12b-4+4=0

We add all the numbers together, and all the variables

-4b=0

b=0/-4

b=0

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