2(4b-5-b)=18

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Solution for 2(4b-5-b)=18 equation: 



2(4b-5-b)=18

We move all terms to the left:

2(4b-5-b)-(18)=0

We add all the numbers together, and all the variables

2(3b-5)-18=0

We multiply parentheses

6b-10-18=0

We add all the numbers together, and all the variables

6b-28=0

We move all terms containing b to the left, all other terms to the right

6b=28

b=28/6

b=4+2/3

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