2(4b-6)=(3b-7)

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Solution for 2(4b-6)=(3b-7) equation: 



2(4b-6)=(3b-7)

We move all terms to the left:

2(4b-6)-((3b-7))=0

We multiply parentheses

8b-((3b-7))-12=0



We calculate terms in parentheses: -((3b-7)), so:

(3b-7)

We get rid of parentheses

3b-7

Back to the equation:

-(3b-7)



We get rid of parentheses

8b-3b+7-12=0

We add all the numbers together, and all the variables

5b-5=0

We move all terms containing b to the left, all other terms to the right

5b=5

b=5/5

b=1

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