2(4b-6)=11(3b-7)

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Solution for 2(4b-6)=11(3b-7) equation: 



2(4b-6)=11(3b-7)

We move all terms to the left:

2(4b-6)-(11(3b-7))=0

We multiply parentheses

8b-(11(3b-7))-12=0



We calculate terms in parentheses: -(11(3b-7)), so:

11(3b-7)

We multiply parentheses

33b-77

Back to the equation:

-(33b-77)



We get rid of parentheses

8b-33b+77-12=0

We add all the numbers together, and all the variables

-25b+65=0

We move all terms containing b to the left, all other terms to the right

-25b=-65

b=-65/-25

b=2+3/5

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