2(4c)+6(c)=192

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Solution for 2(4c)+6(c)=192 equation: 



2(4c)+6(c)=192

We move all terms to the left:

2(4c)+6(c)-(192)=0

We add all the numbers together, and all the variables

30c-192=0

We move all terms containing c to the left, all other terms to the right

30c=192

c=192/30

c=6+2/5

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