2(4c+1)=7(c+1)

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Solution for 2(4c+1)=7(c+1) equation:


Simplifying
2(4c + 1) = 7(c + 1)

Reorder the terms:
2(1 + 4c) = 7(c + 1)
(1 * 2 + 4c * 2) = 7(c + 1)
(2 + 8c) = 7(c + 1)

Reorder the terms:
2 + 8c = 7(1 + c)
2 + 8c = (1 * 7 + c * 7)
2 + 8c = (7 + 7c)

Solving
2 + 8c = 7 + 7c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7c' to each side of the equation.
2 + 8c + -7c = 7 + 7c + -7c

Combine like terms: 8c + -7c = 1c
2 + 1c = 7 + 7c + -7c

Combine like terms: 7c + -7c = 0
2 + 1c = 7 + 0
2 + 1c = 7

Add '-2' to each side of the equation.
2 + -2 + 1c = 7 + -2

Combine like terms: 2 + -2 = 0
0 + 1c = 7 + -2
1c = 7 + -2

Combine like terms: 7 + -2 = 5
1c = 5

Divide each side by '1'.
c = 5

Simplifying
c = 5

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