2(4c+3)=27+5c

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Solution for 2(4c+3)=27+5c equation:


Simplifying
2(4c + 3) = 27 + 5c

Reorder the terms:
2(3 + 4c) = 27 + 5c
(3 * 2 + 4c * 2) = 27 + 5c
(6 + 8c) = 27 + 5c

Solving
6 + 8c = 27 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
6 + 8c + -5c = 27 + 5c + -5c

Combine like terms: 8c + -5c = 3c
6 + 3c = 27 + 5c + -5c

Combine like terms: 5c + -5c = 0
6 + 3c = 27 + 0
6 + 3c = 27

Add '-6' to each side of the equation.
6 + -6 + 3c = 27 + -6

Combine like terms: 6 + -6 = 0
0 + 3c = 27 + -6
3c = 27 + -6

Combine like terms: 27 + -6 = 21
3c = 21

Divide each side by '3'.
c = 7

Simplifying
c = 7

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