2(4c-1)-12=3(c+2)+5

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Solution for 2(4c-1)-12=3(c+2)+5 equation: 



2(4c-1)-12=3(c+2)+5

We move all terms to the left:

2(4c-1)-12-(3(c+2)+5)=0

We multiply parentheses

8c-(3(c+2)+5)-2-12=0



We calculate terms in parentheses: -(3(c+2)+5), so:

3(c+2)+5

We multiply parentheses

3c+6+5

We add all the numbers together, and all the variables

3c+11

Back to the equation:

-(3c+11)



We add all the numbers together, and all the variables

8c-(3c+11)-14=0

We get rid of parentheses

8c-3c-11-14=0

We add all the numbers together, and all the variables

5c-25=0

We move all terms containing c to the left, all other terms to the right

5c=25

c=25/5

c=5

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