2(4c-1)-5=6c+7

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Solution for 2(4c-1)-5=6c+7 equation: 



2(4c-1)-5=6c+7

We move all terms to the left:

2(4c-1)-5-(6c+7)=0

We multiply parentheses

8c-(6c+7)-2-5=0

We get rid of parentheses

8c-6c-7-2-5=0

We add all the numbers together, and all the variables

2c-14=0

We move all terms containing c to the left, all other terms to the right

2c=14

c=14/2

c=7

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