2(4c-1)-6c=10

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Solution for 2(4c-1)-6c=10 equation: 



2(4c-1)-6c=10

We move all terms to the left:

2(4c-1)-6c-(10)=0

We add all the numbers together, and all the variables

-6c+2(4c-1)-10=0

We multiply parentheses

-6c+8c-2-10=0

We add all the numbers together, and all the variables

2c-12=0

We move all terms containing c to the left, all other terms to the right

2c=12

c=12/2

c=6

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