2(4c-1)-8=6c+2

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Solution for 2(4c-1)-8=6c+2 equation:


Simplifying
2(4c + -1) + -8 = 6c + 2

Reorder the terms:
2(-1 + 4c) + -8 = 6c + 2
(-1 * 2 + 4c * 2) + -8 = 6c + 2
(-2 + 8c) + -8 = 6c + 2

Reorder the terms:
-2 + -8 + 8c = 6c + 2

Combine like terms: -2 + -8 = -10
-10 + 8c = 6c + 2

Reorder the terms:
-10 + 8c = 2 + 6c

Solving
-10 + 8c = 2 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
-10 + 8c + -6c = 2 + 6c + -6c

Combine like terms: 8c + -6c = 2c
-10 + 2c = 2 + 6c + -6c

Combine like terms: 6c + -6c = 0
-10 + 2c = 2 + 0
-10 + 2c = 2

Add '10' to each side of the equation.
-10 + 10 + 2c = 2 + 10

Combine like terms: -10 + 10 = 0
0 + 2c = 2 + 10
2c = 2 + 10

Combine like terms: 2 + 10 = 12
2c = 12

Divide each side by '2'.
c = 6

Simplifying
c = 6

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