2(4c-11)=3(c+10)+10

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Solution for 2(4c-11)=3(c+10)+10 equation: 



2(4c-11)=3(c+10)+10

We move all terms to the left:

2(4c-11)-(3(c+10)+10)=0

We multiply parentheses

8c-(3(c+10)+10)-22=0



We calculate terms in parentheses: -(3(c+10)+10), so:

3(c+10)+10

We multiply parentheses

3c+30+10

We add all the numbers together, and all the variables

3c+40

Back to the equation:

-(3c+40)



We get rid of parentheses

8c-3c-40-22=0

We add all the numbers together, and all the variables

5c-62=0

We move all terms containing c to the left, all other terms to the right

5c=62

c=62/5

c=12+2/5

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