2(4c-5)=8c-10

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Solution for 2(4c-5)=8c-10 equation:


Simplifying
2(4c + -5) = 8c + -10

Reorder the terms:
2(-5 + 4c) = 8c + -10
(-5 * 2 + 4c * 2) = 8c + -10
(-10 + 8c) = 8c + -10

Reorder the terms:
-10 + 8c = -10 + 8c

Add '10' to each side of the equation.
-10 + 10 + 8c = -10 + 10 + 8c

Combine like terms: -10 + 10 = 0
0 + 8c = -10 + 10 + 8c
8c = -10 + 10 + 8c

Combine like terms: -10 + 10 = 0
8c = 0 + 8c
8c = 8c

Add '-8c' to each side of the equation.
8c + -8c = 8c + -8c

Combine like terms: 8c + -8c = 0
0 = 8c + -8c

Combine like terms: 8c + -8c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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