2(4d-5)+3=4(d-2)+4d

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Solution for 2(4d-5)+3=4(d-2)+4d equation:



2(4d-5)+3=4(d-2)+4d
We move all terms to the left:
2(4d-5)+3-(4(d-2)+4d)=0
We multiply parentheses
8d-(4(d-2)+4d)-10+3=0
We calculate terms in parentheses: -(4(d-2)+4d), so:
4(d-2)+4d
We add all the numbers together, and all the variables
4d+4(d-2)
We multiply parentheses
4d+4d-8
We add all the numbers together, and all the variables
8d-8
Back to the equation:
-(8d-8)
We add all the numbers together, and all the variables
8d-(8d-8)-7=0
We get rid of parentheses
8d-8d+8-7=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation

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