2(4e-2)=7(e+15)

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Solution for 2(4e-2)=7(e+15) equation: 



2(4e-2)=7(e+15)

We move all terms to the left:

2(4e-2)-(7(e+15))=0

We multiply parentheses

8e-(7(e+15))-4=0



We calculate terms in parentheses: -(7(e+15)), so:

7(e+15)

We multiply parentheses

7e+105

Back to the equation:

-(7e+105)



We get rid of parentheses

8e-7e-105-4=0

We add all the numbers together, and all the variables

e-109=0

We move all terms containing e to the left, all other terms to the right

e=109

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