2(4e-2)=7(e+15)

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Solution for 2(4e-2)=7(e+15) equation:



2(4e-2)=7(e+15)
We move all terms to the left:
2(4e-2)-(7(e+15))=0
We multiply parentheses
8e-(7(e+15))-4=0
We calculate terms in parentheses: -(7(e+15)), so:
7(e+15)
We multiply parentheses
7e+105
Back to the equation:
-(7e+105)
We get rid of parentheses
8e-7e-105-4=0
We add all the numbers together, and all the variables
e-109=0
We move all terms containing e to the left, all other terms to the right
e=109

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