2(4f+2)=4f-12(f-1)

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Solution for 2(4f+2)=4f-12(f-1) equation: 



2(4f+2)=4f-12(f-1)

We move all terms to the left:

2(4f+2)-(4f-12(f-1))=0

We multiply parentheses

8f-(4f-12(f-1))+4=0



We calculate terms in parentheses: -(4f-12(f-1)), so:

4f-12(f-1)

We multiply parentheses

4f-12f+12

We add all the numbers together, and all the variables

-8f+12

Back to the equation:

-(-8f+12)



We get rid of parentheses

8f+8f-12+4=0

We add all the numbers together, and all the variables

16f-8=0

We move all terms containing f to the left, all other terms to the right

16f=8

f=8/16

f=1/2

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