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2(4f+4)=2(2f+6)
We move all terms to the left:
2(4f+4)-(2(2f+6))=0
We multiply parentheses
8f-(2(2f+6))+8=0
We calculate terms in parentheses: -(2(2f+6)), so:We get rid of parentheses
2(2f+6)
We multiply parentheses
4f+12
Back to the equation:
-(4f+12)
8f-4f-12+8=0
We add all the numbers together, and all the variables
4f-4=0
We move all terms containing f to the left, all other terms to the right
4f=4
f=4/4
f=1
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