2(4i+2)=4i-12(i-1)

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Solution for 2(4i+2)=4i-12(i-1) equation: 



2(4i+2)=4i-12(i-1)

We move all terms to the left:

2(4i+2)-(4i-12(i-1))=0

We multiply parentheses

8i-(4i-12(i-1))+4=0



We calculate terms in parentheses: -(4i-12(i-1)), so:

4i-12(i-1)

We multiply parentheses

4i-12i+12

We add all the numbers together, and all the variables

-8i+12

Back to the equation:

-(-8i+12)



We get rid of parentheses

8i+8i-12+4=0

We add all the numbers together, and all the variables

16i-8=0

We move all terms containing i to the left, all other terms to the right

16i=8

i=8/16

i=1/2

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