2(4i+3)-8=10

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Solution for 2(4i+3)-8=10 equation: 



2(4i+3)-8=10

We move all terms to the left:

2(4i+3)-8-(10)=0

We add all the numbers together, and all the variables

2(4i+3)-18=0

We multiply parentheses

8i+6-18=0

We add all the numbers together, and all the variables

8i-12=0

We move all terms containing i to the left, all other terms to the right

8i=12

i=12/8

i=1+1/2

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