2(4j+3)+6=22(1-j)

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Solution for 2(4j+3)+6=22(1-j) equation:


Simplifying
2(4j + 3) + 6 = 22(1 + -1j)

Reorder the terms:
2(3 + 4j) + 6 = 22(1 + -1j)
(3 * 2 + 4j * 2) + 6 = 22(1 + -1j)
(6 + 8j) + 6 = 22(1 + -1j)

Reorder the terms:
6 + 6 + 8j = 22(1 + -1j)

Combine like terms: 6 + 6 = 12
12 + 8j = 22(1 + -1j)
12 + 8j = (1 * 22 + -1j * 22)
12 + 8j = (22 + -22j)

Solving
12 + 8j = 22 + -22j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '22j' to each side of the equation.
12 + 8j + 22j = 22 + -22j + 22j

Combine like terms: 8j + 22j = 30j
12 + 30j = 22 + -22j + 22j

Combine like terms: -22j + 22j = 0
12 + 30j = 22 + 0
12 + 30j = 22

Add '-12' to each side of the equation.
12 + -12 + 30j = 22 + -12

Combine like terms: 12 + -12 = 0
0 + 30j = 22 + -12
30j = 22 + -12

Combine like terms: 22 + -12 = 10
30j = 10

Divide each side by '30'.
j = 0.3333333333

Simplifying
j = 0.3333333333

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