2(4k+2)=4k-12(k-1)

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Solution for 2(4k+2)=4k-12(k-1) equation: 



2(4k+2)=4k-12(k-1)

We move all terms to the left:

2(4k+2)-(4k-12(k-1))=0

We multiply parentheses

8k-(4k-12(k-1))+4=0



We calculate terms in parentheses: -(4k-12(k-1)), so:

4k-12(k-1)

We multiply parentheses

4k-12k+12

We add all the numbers together, and all the variables

-8k+12

Back to the equation:

-(-8k+12)



We get rid of parentheses

8k+8k-12+4=0

We add all the numbers together, and all the variables

16k-8=0

We move all terms containing k to the left, all other terms to the right

16k=8

k=8/16

k=1/2

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