2(4k-4)=3(k+4)

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Solution for 2(4k-4)=3(k+4) equation: 



2(4k-4)=3(k+4)

We move all terms to the left:

2(4k-4)-(3(k+4))=0

We multiply parentheses

8k-(3(k+4))-8=0



We calculate terms in parentheses: -(3(k+4)), so:

3(k+4)

We multiply parentheses

3k+12

Back to the equation:

-(3k+12)



We get rid of parentheses

8k-3k-12-8=0

We add all the numbers together, and all the variables

5k-20=0

We move all terms containing k to the left, all other terms to the right

5k=20

k=20/5

k=4

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