2(4m+1)=3(7m-2)

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Solution for 2(4m+1)=3(7m-2) equation: 



2(4m+1)=3(7m-2)

We move all terms to the left:

2(4m+1)-(3(7m-2))=0

We multiply parentheses

8m-(3(7m-2))+2=0



We calculate terms in parentheses: -(3(7m-2)), so:

3(7m-2)

We multiply parentheses

21m-6

Back to the equation:

-(21m-6)



We get rid of parentheses

8m-21m+6+2=0

We add all the numbers together, and all the variables

-13m+8=0

We move all terms containing m to the left, all other terms to the right

-13m=-8

m=-8/-13

m=8/13

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