2(4m-5)-(6m+)=33

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Solution for 2(4m-5)-(6m+)=33 equation: 



2(4m-5)-(6m+)=33

We move all terms to the left:

2(4m-5)-(6m+)-(33)=0

We add all the numbers together, and all the variables

2(4m-5)-(+6m)-33=0

We multiply parentheses

8m-(+6m)-10-33=0

We get rid of parentheses

8m-6m-10-33=0

We add all the numbers together, and all the variables

2m-43=0

We move all terms containing m to the left, all other terms to the right

2m=43

m=43/2

m=21+1/2

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